Recently, I have learned about the move semantics of C++ 11 from Bo Qian’s YouTuBe Channel. As an “old boy” that is curious to all kinds of new techniques, I definitely would give myself a try.
First of all, I create the following C++ class (which is similar to the one used in Bo Qian’s Video), i.e.,, Note that, all “#include” are omitted.
class exampleA {
int *x;
int size;
public:
// default constructor
exampleA(): x(NULL), size(0) {
std::cout << "Default constructor is called" << std::endl;
}
// constructor from a std::vector
exampleA(const std::vector<int>& vec){
size = vec.size();
x = new int[size];
for (int i = 0;i < size;++ i) x[i] = vec[i];
std::cout << "Create exampleA object from vector" << std::endl;
}
// copy constructor
exampleA(const exampleA& other)
{
std::cout << "Copy constructor is called" << std::endl;
size = other.size;
if (size > 0) {
x = new int[size];
for (int i = 0;i < size;++ i) x[i] = other.x[i];
}else
{
x = NULL;
}
}
// move constructor
exampleA(exampleA&& other)
{
std::cout << "Move constructor is called" << std::endl;
size = other.size;
x = other.x;
other.size = 0;
other.x = NULL;
}
// deconstructor
~exampleA() {
if (x != NULL) delete [] x;
x = NULL;
size = 0;
std::cout << "Deconstructor is called" << std::endl;
}
// friend function: overloading operator <<
friend std::ostream& operator<<(std::ostream& os, const exampleA& a);
};
// definition of (or implementation of) overloading operator <<
std::ostream& operator<<(std::ostream& os, const exampleA& a){
for (int i = 0;i < a.size;++ i) os << a.x[i] << " ";
return os;
}
Then, I defined a function that returns an exampleA object and another function that uses an object from the class exampleA as a parameter as follows.
// function to create an exampleA object
exampleA createObject(){
exampleA a(std::vector<int>(10, 1));
return a;
}
// function uses an exampleA object as a parameter
void passByValue(exampleA a) {
std::cout << a;
}
Next, I though the moment to witness the miracle (Chinese: 见证奇迹的时刻) was coming. I created the following use cases to verify my understanding.
int main()
{
exampleA a(std::vector<int>(10, 1));
passByValue(a);
std::cout << "======================================\n\n";
passByValue(createObject());
return 0;
}
Before “witnessing the miracle”, let us first do some simple analysis to figure out what the “miracle” is. According to the above use cases, we first create an exampleA object – i.e., a
– from an std::vector
. Then we passed a
to the function passbyValue
by value, since a
is a lvalue
, we would expect the copy constructor to be called. And then, we passed a rvalue
createObject()
to the function passbyValue
, we would expect the move constructor to be called.
However, the following presents the output from running the above example (by using g++ -std=c++11 example.cpp -o example && ./example
)
Create exampleA object from vector
Copy constructor is called
1 1 1 1 1 1 1 1 1 1
Deconstructor is called
======================================
Create exampleA object from vector
1 1 1 1 1 1 1 1 1 1
Deconstructor is called
Deconstructor is called
Unfortunately, we failed to witness the most important part of the miracle, i.e., the move semantics.
After Google, Google, … and Google again, I eventually found “the chief culprit”. It is the copy elision feature of the compiler. Now, it is really the moment to witness the miracle. The following gives the final outputs after disabling the copy elision (add a flag -fno-elide-constructors
, that is to run g++ -fno-elide-constructors -std=c++11 example.cpp -o example && ./example
).
Create exampleA object from vector
Copy constructor is called
1 1 1 1 1 1 1 1 1 1
Deconstructor is called
======================================
Create exampleA object from vector
Move constructor is called
Deconstructor is called
Move constructor is called
1 1 1 1 1 1 1 1 1 1
Deconstructor is called
Deconstructor is called
Deconstructor is called
From the above outputs, you can see that the move constructor was called twice. First call was during the returning from the function createObject
, and the other one is during passing value to the function passByValue
.